An underground mine elevator descends 12% of the total depth every minute. the total depth of the elevator is 75 meters below the ground. How many meters below the ground is the elevator after 2 mins a. -18 meters
b. -9 meters
c. -4.5 meters
d. -22.5

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°

a.)the line for function b is steeper

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.