34 POINTS, BRAINLIEST, PLEASE HAALLPPP TT^TT PLEASE don`t respond without an answer!
A basketball is thrown upward from a height of 1.8 m at a velocity of 12 m/s. How long until it reaches the ground?
(Recall: h(t)=-4.9t^2-v_0 t+h_0, where v_0 is initial velocity and h_0 is initial height.)

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

a: inscribed angles

step-by-step explanation:

i reviewed this question with a peer and teacher, seems to be correct, me later

the answer would be 44.79

plz mark brainliest

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)