Write an equation of a line given two points. Identify the slope and the y intercept separately. (1) (-1,-9), (2,0)

please help me.

The equation is y=3x-6. 3 being slope, -6 being y-intercept

Step-by-step explanation:

use the equation y=mx+b. To find the slope you use the method y2-y1 and x2-x1. so 0-(-9) = 9 and 2-(-1)=3, so 9/3 simplified is 3. you can now fill out some of your equation, y=3x+b. to find y intercept you plug in one of the points like (2,0) so since 0=y ans 2=x you plus that in 0=3(2)+b. start off in the parenthesis 3×2=6. 0=6+b subtract 0-6=-6 so your equation is y=3x-6

step-by-step explanation:

their are no angles. sorry cant .

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.