How do solve this problem? find an equation of a line parallel to the given line and contains the given point. Write the equation in slope–intercept form. line 2x + 5y= -10 point (10, 4)

y=-2/5x+8

Step-by-step explanation:

Step 1: Begin by changing the equation into slope-intercept form. Subtract 2x to both sides to get 5y=-10-2x. Divide 5 to both sides to isolate the variable, y. You should get y=-2/5x-2.

Step 2: Because we are looking for a line parallel to the given line, the slope should be the same, but the y-intercept should be different. Remove -2 to replace it with b, so it's unknown. The equation should be y=-2/5x+b. Plug in the ordered pair, (10, 4), into the equation to get 4=-2/5(10)+b. Multiply -2/5 and 10 to get -4. Add -4 to both sides and b=8. Plug in 8 and your final equation should be y=-2/5x+8.

1. 34

2. 268

3. x=14.4

step-by-step explanation: