Does anyone know how to do this I’m confused

The simplest polynomial with these roots is

f(x) = (x + 1)² (x - 3)

Expand the right side:

f(x) = x³ - x² - 5x - 3

So one sequence of coefficients (the answers you have to fill in) might be {+1, -1, -5, -3}.

If those choices aren't available, you can also multiply f(x) by any appropriate constant c, since both

(x + 1)² (x - 3)

and

c (x + 1)² (x - 3)

and by extension, so would

c f(x) = c x³ - c x² - 5c x - 3c

have the same roots.

For example, if you pick c = -1, then you could submit {-1, +1, +5, +3}. If c = 2, then you could use {+2, -2, -10, -6}. And so on.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|