A potting mixture contains 12.0% peat moss and 6.00% vermiculite. How much peat moss and how much vermiculite must be added to 100lb of this mixture to produce a new mixture having 15.0% peat and 15.0% vermiculite?

Answer is 3% more peat and 9% more vermiculite.

Step-by-step explanation:

The weight of the initial potting mixture is not given, but the percentage amounts of peat moss & vermiculite are given.

The weight of the new potting mixture is 100lb.

For the new mixture to have 15% peat and 15% vermiculite,

The amount of peat that must be added is 3% of the peat in the initial mixture.

Hint: subtract 12 from 15. Retain the percentage sign.

The amount of vermiculite that must be added is 9% of the vermiculite in the initial mixture.

Hint: subtract 6 from 15. Retain the percentage sign, as that is the scale of measurement here.

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316