A plane leaves an airport traveling at 400 mph in the direction N 45° E. A wind is blowing at 40 mph in the direction N 45° W. What is the ground speed of the plane?

the answer is 402 mph <3

Step-by-step explanation:

it's helpful to draw diagram but

use the law of cosines to find the ground speed.

G²=400²+40²-2(400)(40)cos(90)

*400 & 40 are given values

*90 degrees is from the sum of the angles

G=√400²+40²-2(400)(40)cos(90)

type it in ur calculator or mathw4y or something, u get G= 401.99 or 402

B) 402 mph

Step-by-step explanation:

got it right on edge :)