If a ship travels north for 18 miles and east for 12 miles, to the nearest tenth, approximately how far away is it
from it's starting point?

The ship is approximately 21.6 miles away from its starting point

Step-by-step explanation:

∵ The North and the East are perpendicular

→ That means the distance between the starting position and

   the ending position shows a hypotenuse of a right triangle which

   its legs are the distances due to North and East

∵ The ship travels north for 18 miles

∴ leg1 = 18 miles

∵ The ship travels east for 12 miles

∴ leg2 = 12 miles

→ By using Pythagoras Theorem

∵ (hypotenuse)² = (leg1)² + (leg2)²

∴ (hypotenuse)² = (18)² + (12)²

∴ (hypotenuse)² = 324 + 144

∴ (hypotenuse)² = 468

→ Take √  for both sides

∴ hypotenuse = 21.63330765

→ Approximate it to the nearest tenth

∴ hypotenuse = 21.6 miles

∵ The hypotenuse of the right triangle represents the distance from

   the starting position to the ending position

∴ The ship is approximately 21.6 miles away from its starting point

4038

step-by-step explanation:

pleaze mark brainliest!

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get