The altitude of an isosceles triangle bisects the base and measures 10ft. If the base of the triangle measures 16ft, calculate: a) the area of the triangle b) and one side of the triangle.

Step-by-step explanation:

the formula for calxulating the area if the isosceles triangle is expressed as;

b is the base of the triangle

h is the altitude

Given

b = 16ft

h = 10ft

Substitute

A = 1/2 * 16 * 10

A = 8*10

A = 80ft²

Hence the area of the triangle is 80ft²

b) To get the measure of one side of the triangle, we will use the pythagoras theorem. Let s be the slant side

s² = h²+(b/2)²

s² = 10²+(16/2)²

s² = 10²+(8)²

s² =100+64

s² =164

s = √164

s = 12.8ft

Hence one side of the triangle is 12.8ft

rectangle that is ther answer you

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this