If c is a real number and if 1 + i is a solution of the equation x^2 -2x + c = 0, what is the value of c?

c = 2

Step-by-step explanation:

Substitute x = 1 + i into the equation

(1 + i)² - 2(1 + i) + c = 0 ← distribute left side

1 + 2i + i² - 2 - 2i + c = 0 ( note that i² = - 1 )

1 + 2i - 1 - 2 - 2i + c = 0 ← collect like terms on left

- 2 + c = 0 ( add 2 to both sides )

c = 2

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead