Suppose that a random sample of size 64 is to be selected from a population with mean 40 and standard deviation 5. (a) What is the mean of the xbar sampling distribution

Sample mean (xbar) = 40

Step-by-step explanation:

Given that :

Sample size (n) = 64

Population mean (μ) = 40

Standard deviation (σ) = 5

The sample mean is equal to the population mean according to the central limit theorem.

The sample standard deviation = standard error = ;

Standard Error = σ / √n

Standard Error = 5 / √64

Standard Error = 5 / 8

Standard Error = 0.625

step-by-step explanation:

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times