Mathematics, 04.11.2020 19:00 baeethtsadia
Suppose 56V% of politicians are lawyers. If a random sample of size 787787 is selected, what is the probability that the proportion of politicians who are lawyers will differ from the total politicians proportion by greater than 4%4%
Answers: 2
be th sample proportion.![P(|\hat{p}-0.56|0.04)=P(-0.04\hat{p}-0.560.04)=\\\\ P(-0.04+0.56\hat{p}0.04+0.56)\\\\=P(0.52\hat{p}0.60)\\\\=P(\dfrac{0.52-0.56}{\sqrt{\dfrac{0.56(1-0.56)}{787}}}\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\dfrac{0.60-0.56}{\sqrt{\dfrac{0.56(1-0.56)}{787}}})\\\\=P(-2.26z2.26)\ \ \ [Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\=1-P(-2.26](/tpl/images/0866/8645/3d87b.png)
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Suppose 56V% of politicians are lawyers. If a random sample of size 787787 is selected, what is the...
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