Ab  passes through  a(-3, 0) and  b(-6, 5).  what is the equation of the line that passes through the origin and is parallel to ab? a.  5x  − 3y  = 0b.  -x  + 3y  = 0c.  -5x  − 3y  = 0d.  3x  + 5y  = 0e.  -3x  + 5y  = 0

C.  -5x − 3y = 0

Step-by-step explanation:

A(-3, 0) and B(-6, 5)

First we find the slope of line AB

Slope of the line parallel to AB =  slope of line AB

When the lines are parallel then their slope are equal

So the slope of line parallel to AB =

The line passes through the origin (0,0)

Use equation y-y1= m (x-x1)

m = -5/3 , x1=0 and y1=0

multiply the whole equation by 3

3y = -5x

Subtract 3x from both sides

0=-5x-3y

-5x - 3y =0

l.jnl.j/n.m,lm,

step-by-step explanation:

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: