A car in stop-and-go traffic starts at rest, moves forward 12 m in 8.0 s, then comes to rest again. The velocity-versus-time plot for this car is given in the figure. What distance does the car cover in the first 4.0 seconds of its motion?

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

v=1788.75

step-by-step explanation:

i belive that is the answer