The derivation for the equation of a parabola with a vertex at the origin is started below. = StartRoot (x minus 0) squared + (y minus p) squared EndRoot = StartRoot (x minus x) squared + (y minus (negative p)) squared EndRoot (x)2 + (y – p)2 = (0)2 + (y + p)2 x2 + y2 – 2py + p2 = y2 + 2py + p2 If the equation is further simplified, which equation for a parabola does it become? x2 = 4py x2 = 2y2 + 2p2 y2 = 4px y2 = 4py

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

6.5

step-by-step explanation:

you said it was in the question

~courtney

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)