Writing equations of lines

Step-by-step explanation:

Equation of straight line is y=mx+c

choose any two points on straight line

for me I choose:(-3,11) and (3,-1)

use these two points to find gradient,m.

m= (-1-11)/(3-(-3))

m= -2

now, y=-2x+c

choose any point on the straight line

I choose point (3,-1)

sub the point into the equation to find c

-1=-2(3)+c

c=5

equation: y=-2x+5

1,645,493,059.35

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)