A bus makes a stop at 2:30, letting off 11 people and letting on 8. The bus makes another stop ten minutes later to let off 5 more people. How does the number of people on the bus after the second stop compare to the numbers of the people on the bus before the 2:30 stop ?

The actual number of passengers on the bus falling by 8 after the second stop

Step-by-step explanation:

Assume that the total passengers on the bus before 2:30 was x

At 2:30:

11 passengers got off and 8 got on.

So, the number of passengers

= x - 11 + 8

= x - 3

10 minutes later:

5 passengers got off the bus

So, the number of passengers

number of passengers = (x - 3) - 5

number of passengers = x - 8

now by comparing,

The actual number of passengers on the bus falling by 8 after the second stop

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.