Stanley practices his running, swimming and biking every day. During these practices he runs at 9 mph, bikes at 16 mph and swims at 2.5 mph. Yesterday he ran for half an hour longer than he swam, and his biking time was twice his running time. How long did Stanley run, swim, and bike yesterday if the total distance he covered was 64 miles? (a) If Stanley swam for t hours yesterday, what was his running time?

(b) In terms of t, how long did Stanley bike yesterday?

(c) What distance did Stanley covered while swimming?

(d) What distance did Stanley covered while running?

(e) What distance did Stanley covered while biking?

(f) What was the total distance Stanley covered during practices in terms of t?

(g) Write the equation that will allow you to find the practice time.

(h) For how long did Stanley swim, run, and bike yesterday?

I understand if you don't know more than one, I just need you guys to answer at least one problem. I will of course be awarding brainiest, as well as a TON of points. This is dues tomorrow people, please help me.

(a) Stanley's running time was 0.5 + t

(b) Stanley biked for = 1 + 2·t hours

(c) The distance Stanley covered while swimming = 2.5 miles

(d) The distance Stanley covered while running = 13.5 miles

(e) The distance Stanley covered while biking = 48 miles

(f) Total distance Stanley covered during practice in terms of t = 43.5·t + 20.5

(g) The equation for finding the practice time is 64 = 43.5·t + 20.5

(h) Stanley swam, ran and biked for a total time of 5.5 hours

Step-by-step explanation:

The speed with which Stanley runs = 9 mph

The speed with which Stanley bikes = 16 mph

The speed with which Stanley swims = 2.5 mph

The time Stanley (he) spent running = 30 minutes + The time he spent swimming

The time Stanley (he) spent biking  = 2 × The time The time (he) spent running

Let the time Stanley spent swimming = t in hours

(a) The time he spent running = 30 minutes + t = 0.5 + t

The time he spent running = 0.5 + t

Stanley's running time was 0.5 + t

(b) The time Stanley spent biking  = 2 × (30 minutes + t) = 2 × (0.5 + t)

The time Stanley spent biking  = 2 × (0.5 + t) = 1 + 2·t

The time Stanley spent biking  = 1 + 2·t

Stanley biked for = 1 + 2·t hours

Therefore, given that distance = Speed × Time, we have

t × 2.5 + 9×(0.5 + t) + 16 × (2 × (0.5 + t)) = 64

2.5·t + 4.5 + 9·S + 32·t + 16 = 64

43.5·t + 20.5 = 64

43.5·t = 64 - 20.5 = 43.5

43.5·t = 43.5

t = 43.5/43.5 = 1

t = 1 hour

The time Stanley spent swimming = t = 1 hour

The time he spent running = 0.5 + t = 0.5 + 1.5 = 1.5

The time Stanley spent running = 1.5 hours

The time Stanley spent biking  = 2 × (0.5 + t) = 2 × (0.5 + 1) = 2 × 1.5 = 3

The time Stanley spent biking  = 3 hours

(c) The distance Stanley covered while swimming = Stanley's swimming speed × The time Stanley spent swimming

∴ The distance Stanley covered while swimming = 2.5 mph × 1 hour = 2.5 miles

The distance Stanley covered while swimming = 2.5 miles

(d) The distance Stanley covered while running = Stanley's running speed × The time Stanley spent running

The distance Stanley covered while running = 9 mph × 1.5 hours = 13.5 miles

The distance Stanley covered while running = 13.5 miles

(e) The distance Stanley covered while biking = Stanley's biking speed × The time Stanley spent biking

The distance Stanley covered while biking = 16 mph × 3 hours =  48 miles

The distance Stanley covered while biking = 48 miles

(f) The total distance Stanley covered during practice in terms of t is given as follows;

Given that distance = Speed × Time, we have

Total distance = t × 2.5 + 9×(0.5 + t) + 16 × (2 × (0.5 + t))

Total distance =2.5·t + 4.5 + 9·S + 32·t + 16

Total distance Stanley covered during practice in terms of t = 43.5·t + 20.5

(g) The equation for finding the practice time is given as follows;

Total distance Stanley covered during practice = 64 = 43.5·t + 20.5

∴ The equation for finding the practice time is 64 = 43.5·t + 20.5

(h) Stanley swam, ran and biked for a total time, , given as follows;

= The time Stanley spent swimming + The time Stanley spent running + The time Stanley spent biking

∴ = 1 + 1.5 + 3 = 5.5 hours.

a) $ 9.50

b) 17

c) y-intercept (0, 12). this is the initial amount of money that joe had prior to playing any game.

d) x-intercept ( 24, 0). this is the number of games that joe will play before he depletes the initial amount of money that he had.

e) slope is -0.5. joe's balance will reduce by 0.5 for every game that he plays.

f)

domain; [0,24]

range; [0,12]

g) x + 2y = 24

step-by-step explanation:

a)

if joe plays 5 games, this will imply that x = 5. substitute x = 5 in the equation and solve for y;

y = -.50x + 12

y = -0.50(5) + 12

y = 9.50

b)

if joe leaves the arcade with $3.50, this will mean that y = 3.50. plug in y = 3.50 in the given equation and solve for x;

y = -.50x + 12

3.50 = -0.50x + 12

0.50x = 12 - 3.50

0.5x = 8.5

x = 17

c)

the function given is   y = -.50x + 12.

the y-intercept is the point where the graph of this function will intersect the y-axis. at this point, the value of x is usually 0. plug in x = 0 in the given equation and determine y;

y = -0.50(0) + 12

y = 12

the y-intercept is thus (0, 12). this is the initial amount of money that joe had prior to playing any game.

d)

the x-intercept refers to the point where the graph of a function intersects with the x-axis. at this point, the value of y is 0. substitute y = 0 in the given equation and solve for x;

0 =   -.50x + 12

0.5x = 12

x = 24

x-intercept ( 24, 0). this is the number of games that joe will play before he depletes the initial amount of money that he had.

e)

the slope of the given equation is -0.5. the equation has been given in slope-intercept form. thus the slope is simply the coefficient of x.

joe's balance will reduce by 0.5 for every game that he plays. this is the interpretation of the slope.

f)

domain is the set of x values for which the function is real and defined. the domain will thus be; [0,24]. this will restrict the balance to only assume positive values.

on the other hand, the range is the set of y values for which a function is real and defined. the range in our case will be [0,12]. joe can have between $0 and $12 balance.

g)

the standard form of the equation of a straight line is;

ax + by = c

where a, b, and c are integers.

our equation is given as;

y = -.50x + 12

re-writing the equation we have;

0.5x + y = 12

divide all through by 0.5;

x + 2y = 24

i can not answer the question due to the fact that you spelled "carton" as "cartoon", a cartoon is something you watch on tv, a carton is a box that holds things. and also you've been waiting for this question for a while so why don't you get off your lazy a** and try to figure it out for yourself for once!

step-by-step explanation:

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look above, and leave your comments down below, and don't for get a five stars and a and brainliest xd

sorry for the stars in the middle of words its because it wouldn't let me submit. xd