Factorise 6^3+11x^2-12x-5
PLEASE ANSWER URGENT

(x - 1)(3x + 1)(2x + 5)

Step-by-step explanation:

Given

6x³ + 11x² - 12x - 5

The sum of the coefficients = 6 + 11 - 12 - 5 = 0

Hence x = 1 is a root and (x - 1) a factor

Dividing 6x³ + 11x² - 12x - 5 by (x - 1) using Synthetic division

1 | 6   11   - 12   - 5

     ↓    6    17      5

     6   17    5       0 ← remainder

Quotient = 6x² + 17x + 5

Thus

6x³ + 11x² - 12x - 5 =(x - 1)(6x² + 17x + 5) = (x - 1)(3x + 1)(2x + 5)

if you was gonna solve for a, a is a   < -12

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x