How much salt is in a mixture containing 10 gallons of an 11% salt solution and 6 gallons of a 7% salt solution? I think I can solve it but forming the equation is where I have problems.

Step-by-step explanation:

There really isn't an equation because there isn't an unknown. If we create a table, the "equation" that you are talking about will be come apparent. Let's call the 2 solutions Sol 1 and Sol 2:

                      Gallons of solution    *        % salt          =         Gallons of salt

Sol 1  

Sol 2

If we fill in this table according to the info we are given, we have 10 gallons of the 11% solution, and 6 gallons of the 7% solution, so

                     Gallons of solution       *       % salt         =        Gallons of salt

Sol 1                        10                                     .11            =        1.1 gallons of salt

Sol 2                        6                                     .07           =        .42 gallons of salt

We multiply the Gallons of solution by the % salt to get the gallons of salt. There are 1.1 gallons of salt in solution 1 and .42 gallons of salt in solution 2, so in the mixture (which is 16 gallons) there is 1.1 + .42 gallons of salt, which is 1.52 gallons of salt.

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation:

answer: the answer is e

step-by-step explanation: