Use the ogive to approximate (a) the number in the sample, (b) the location of the greatest increase in frequency.

Step-by-step explanation:

A). Number of samples given in the ogive = Number of points given n the graph

    Number of points plotted on the graph = 16

    Therefore, number of samples given = 16

B). Frequency at a point where weight of the pumpkins is 23.5 = 10

    Frequency at a point where weight of the pumpkin is 24.5 = 23

    Increase in frequency = 23 - 10 = 13

   None other points have the increase more than the given points.

Location of the greatest increase in the frequency is between the weights 23.5 - 24.5 pounds.

The number of samples is 16, and the location of greatest increase in frequency is 23.5 to 24.5.

We are provided with an ogive curve. In the x-axis, we have weight in pounds and y-axis represents frequency.

(a).

Now, the number of points on the ogive represents the number of sample.

So, the number of points on the curve is 16 which is also the number of samples.

(b).

The greatest increase in frequency is represented in the range 23.5 to 24.5.

The greatest hike in frequency is about 10.

Therefore, the number of samples is 16, and the location of greatest increase in frequency is 23.5 to 24.5.

To know more about the ogive curve:

link

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1