14. С. Н. + о,
->
со,
Н,0

beta decay is the answer

it's 3.2 on edge, i just took the test.

the complete reaction for the formation of aluminum oxide is as follows;

4al + 3 > 2

so if the molar mass of the is 32.0 g/mol and

so, to form 3.80 mol of

(3.80 mol ) x (3 mol ) x (32.0 g )

dividing by 2 because two moles of will be formed;

∴ 364.8/2   = 182.4g