I need help please! If m∠ABD=76°, what are m∠ABC and m∠DBC? If m∠JKH=77° then m∠NDF=__

m<ABC = 41°

m<DBC = 35°

m<NDF = 77°

Step-by-step explanation:

Problem 1:

Given, m<ABD = 76°, m<ABC = (7x - 1), m<DBC = (5x + 5)

m<ABC + DBC = m<ABD (angle addition postulate)

(substitution)

Solve for x

Collect like terms

Subtract 4 from each side

Divide each side by 12

Find m<ABC

m<ABC = (7x - 1)

Plug in the value of x

m<ABC = 7(6) - 1 = 42 - 1 = 41°

Find m<DBC

m<DBC = (5x + 5)

Plug in the value of x

m<DBC = 5(6) + 5 = 30 + 5 = 35°

Problem 2:

<JKH and <NDF are corresponding angles. Corresponding angles are congruent.

Given that m<JKH = 77°, m<NDF = 77° (corresponding angles are equal).

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).