5. Three times the width of a certain rectangle exceeds twice its length by two inches. Four times its length is twelve more than its perimeter. Write a system of equations that could be used to solve this problem. (hint: P = 2L + 2W)
A. 3W = 2L + 2
2L = 2W + 12

B. 3W + 2 = 2L
4L = P - 12

C.3W = 2L + 2
4L + 12 =P

D. 2W + 2 = 2L
4L = 12 + P

E. 3W + 2 = 2L
4L = 12 + P

F. 2L - 2 = 3W
P = 4L - 12
plsss help