Use the Alternating Series Remainder Theorem to determine the smallest number of terms required to approximate the sum of the series with an error of less than 0.001. [infinity] (−1)n + 1 n2 n = 1

at N ≥ 6

Step-by-step explanation:

Error permissible = 0.001

The series = infinity  

at ( N + 1 ) ! > 1000  the inequality N ≥ 6 is valid and holds

attached below is the detailed solution using alternating series remainder

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.