Give the values of Xmin, Xmax, Ymin, and Ymax for the screen, given the values for Xscl and Yscl. Xscl = 10, Yscl = 10

C] X min and X max = (-300, 300) and Y min and Y max = (-400, 400)

Xmin, Xmax, Ymin and Ymax denote minimum and maximum values of X and Y respectively.

As x and Y scale are 10 each, the minimum and maximum values can be found by multiplying the units with respective scales.

On X (Horizontal Axis), there are 3 units of line segments each on both left & right sides of origin.

Hence X min & X max = (0 - 300, 0 + 300) = (-300, +300) respectively.

On Y (Vertical Axis), there are 4 units of line segments each on both upwards & downwards sides of origin.

Hence Y min & Y max = (0 - 400, 0 + 400) = ( -400, + 400) respectively.

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Option C.

Step-by-step explanation:

Xmin, Xmax, Ymin, and Ymax represent the minimum/maximum values that X and Y can take.

We know that the scale in Y and X is 10.

This means that each mark in each axis represents 10 units.

Now, let's go to the vertical axis (y-axis)

Counting from the (0, 0) we can count:

4 marks up

4 marks down.

So if each mark represents 10 units, 4 marks are 40 units.

Then the range for Y is {-40, 40}

Now for the horizontal axis.

We can count 3 marks on each side, and with the same reasoning as before, we can find that the range for X is: {-30, 30}

Then we have that:

Xmin = -30

Xmax = 30

Ymin = -40

Ymax = 40

Now, as a point is defined as (X, Y)

This region can be written as:

{Xmin, Xmax} by {Ymin, Ymax}

or, replacing the values:

{-30, 30} by {-40, 40)

So the correct option is C.

1/3 + 1/5 = 8/15.

step-by-step explanation:

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this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of