How many four-character passwords can be formed using the characters A, B, C, 1, 2 if the characters can be repeated

625 four-character passwords can be formed.

----------------------------

Each character of the password is independent of previous characters, which means that the fundamental counting principle is used to solve this question.

Fundamental counting principle:

States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.

----------------------------

Thus, the number of passwords is:

625 four-character passwords can be formed.

A similar question is given at link

Work Shown:

The set {A,B,C,1,2} has five items. There are four slots to fill.

So we have 5^4 = 5*5*5*5 = 625 different possible passwords where the characters can be repeated.

597

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !