Write an equation of the line that passes through the point (5, –8) with slope 5. A. y−5=5(x+8) B. y+8=−5(x−5) C. y−5=−5(x+8) D. y+8=5(x−5)

D

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 5 and (a, b) = (5, - 8 ), thus

y - (- 8) = 5( x - 5), that is

y + 8 = 5(x - 5) → D

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4