8.Find the nature of the roots of the quadratic equation (1 Point)

2 − 5 − 7 − 0x2 − 5x − 7 − 0

Imaginary

Real and Equal

Real and Unequal

None of These

please give the answer as fast as you can

please

Real and unequal

Step-by-step explanation:

We are tasked with finding the nature of the roots of the given quadratic equation.

The given quadratic equation is;

x^2 -5x -7

Firstly, we should know that we cannot solve this by factorization, as we will run into problems.

Now the catch is, although we cannot solve by factorization, we can solve by using the quadratic formula.

Now let’s check if our roots are imaginary or real.

For the roots to be imaginary or real, we will work with calculating the value of the expression b^2 -4ac

The value of this would tell us the nature of the roots. While a negative value would tell us the roots are imaginary, a positive value will tell us the roots are real.

So from the question, b = -5( coefficient of x) , while c = -7 and a = 1 ( coefficient of x^2)

Plugging these values into the equation, we have;

-5^2 - 4(1)(-7) = 25 + 28 = 53

This tells us the roots are real

The last issue is to know if the roots are equal or not.

The roots cannot be equal. This is because the term b^2 - 4ac would be in the root and yield a positive and a negative value which cannot give equal answers when added to (-b)

This from the quadratic formula;

x = {-b ± √(b^2-4ac)}/2a

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!