At the same time, Sam and Fred who are 168 miles apart begin moving toward each other. Find the number of hours before they meet if Sam runs 12 mph and Fred runs 9 mph.

8 hours

Step-by-step explanation:

Let x be the time before they meet ( in hours)

Speed of Sam = 12 mph

Sped of Fred = 9 mph

Distance = Speed × time

Distance covered by Sam in x hours = 12x

Distance covered by Fred in x hours = 9x

                                               (Distance)     (rate1) (time1)          (rate2) (time2)  

Total distance between them: 168             =     12      x        +      9    x

Hence,  the number of hours before they meet if Sam runs 12 mph and Fred runs 9 mph. = 8

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58