Apply the Pythagorean Theorem to find the distance between points B and C. A) 18 units B) 55 units C) 64 units D) 73 units

Step-by-step explanation:

Notice that A, B, and C constitute the vertices of a right angle triangle, with the right angle at the vertex A.

If we count the number of squares separating B and A (one of the legs of the right angle triangle) we find 8 units.

If we count the number of squares separating C from A (the other leg of the right angle triangle), we get: 3 units.

Then, we apply the Pythagorean theorem to find that length of the triangle's hypotenuse which is the segment BC:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.