2.A 1998 Pontiac Grand-Am depreciates in value by 18% on average each year. If the car originally sold for $19995 in 1998, how much would the car be worth in 2012?

Amount of car in 2012 = $1,242.55 (Approx)

Step-by-step explanation:

Given:

Rate of depreciation(d) = 18% = 0.18

Amount of car in 1998 = $19,995

Find:

Amount of car in 2012

Computation:

Number of year(n) = 14 year

Amount of car in 2012 = 19,995[1-0.18]¹⁴

Amount of car in 2012 = 19,995[0.82]¹⁴

Amount of car in 2012 = 19,995[0.0621432458]

Amount of car in 2012 = 1,242.5542

Amount of car in 2012 = $1,242.55 (Approx)

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

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