Solve the following question The difference of two numbers is 12 and their sum is 20 find the numbers

16 and 4

Step-by-step explanation:

Let (x+y) =20 and (x-y)=12 then:

Isolate for x in each equation

   x=20-y and x=12+y

Set the equations to equal each other since the value of x should be the same for both

   20-y = 12+y

Rearrange so that y is on one side and the numbers are on the other

   8 = 2y

   y= 8/2

   y= 4

Now  substitute the y- value back into either of the original equations

   x+y= 20

   x+4 = 20

Rearrange and isolate  x

   x = 20-4

   x = 16

So the two values are 16 and 4

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5