What are the zeroes of f(x) = x2 − 6x + 8? (4 points) x = −4, 2 x = −4, −2 x = 4, 2 x = 4, −2

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Third option. x = 2, and x = 4.

Step-by-step explanation:

Find the zeros of this quadratic equation by factoring:

f(x) = x² - 6x + 8

Becomes:

f(x) = (x - 4)(x - 2)

Set each factor equal to 0 to solve for the roots;

x - 4 = 0

x = 4

x - 2 = 0

x = 2

Therefore, the zeros of this equation are at x = 2, and x = 4.

x=4  x=2

Step-by-step explanation:

f(x) = x^2 − 6x + 8

To find the zeros, set equal to zero

0  = x^2 − 6x + 8

Factor

What 2 numbers multiply to 8 and add to -6

-4*-2 = 8

-4+-2 = -6

0 = ( x-4) (x-2)

Using the zero product property

x-4 =0    x-2=0

x=4  x=2

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step-by-step explanation:

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all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: