I NEED HELP PLEASE, THANKS! :) A projectile is fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. How long will it take for the projectile to reach the ground? (Show work)

  4.097 s

Step-by-step explanation:

The formula for ballistic motion usually used is ...

  h(t) = -4.9t² +v₀t +s₀

where v₀ and s₀ are the initial vertical velocity and height, respectively. Here, we have v₀ = (35 m/s)sin(35°) and s₀ = 0. We want to solve for h(t) = 0.

  0 = -4.9t² +35sin(35°)t = t(-4.9t +35sin(35°))

This is true for t=0 and for ...

  t = 35sin(35°)/4.9 ≈ 4.09697 . . . seconds

It will take about 4.097 seconds for the projectile to reach the ground.

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Comment on the graph

Desmos has a setting option for angles in degrees. That is what we used here.

5+2x=a

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