PLS HURRY The total amount of water a tank can hold is 14 and one-half gallons. Raul wants to find out how many 1 and one-fourth-gallon buckets of water can be used to fill the tank. Which expressions could be used to represent this scenario? Select two options.. StartFraction 29 over 2 EndFraction divided by StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 4 over 5 EndFraction StartFraction 2 over 29 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction divided by StartFraction 4 over 5 EndFraction

[29 over 2 divided by 5 over 4] = 29/2 ÷ 5/4 (A)

[29 over 2 times 4 over 5] = 29/2 × 4/5 (C)

Step-by-step explanation:

The total amount of water a tank can hold is 14 and one and one-half gallons = 14½

We are to determine the number of 1/4 gallon buckets of water that can be used to fill the tank.

To find this, we would divide 14½ by 1¼ = 14½ ÷ 1¼

Convert 14½ and 1¼ to improper fraction

14½ = [(14×2)+1]/2 = 29/2

1¼ = [(1×4)+1]/4 = 5/4

14½ ÷ 1¼ =29/2 ÷ 5/4

Then we find the inverse of ¼ to convert the division to multiplication

= 29/2 × 4/5 = 116/10

= 11.6

14½ ÷ ¼ = 11.6

Therefore 11.6 gallons of ¼ buckets of water can be used to fill the tank.

But the two expressions that could be used to represent this scenario to get the answer from the options = 29/2 ÷ 5/4 (A)

[29 over 2 divided by 5 over 4]

29/2 × 4/5 (C)

[29 over 2 times 4 over 5]

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.