Can someone pls help, I know this is kind of a lot but I’ve been stuck on this for a while now. The data in the table can be modeled by a quadratic function. Find the function that would fit the data.

The number of hours Temperature

after midnight

6 58

8 68

10 76

12 82

14 84

16 81

18 75

After completing the regression using this information the value of a is (__), the value of b is (__), and the value of c is (__). The equation for the situation is f(x)= (__). Use the equation to predict the temperature one hour after midnight.

9514 1404 393

  (a, b, c) = (-0.425595, 11.7321, 2.16667)

  f(x) = -0.425595x² +11.7321x +2.16667

  f(1) ≈ 13.5

Step-by-step explanation:

A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.

Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...

  a = -0.425595

  b = 11.7321

  c = 2.16667

so

  f(x) = -0.425595x² +11.7321x +2.16667

and f(1) ≈ 13.5

_____

Additional comment

Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer: what are the following choices