In a certain liberal arts college with about 10,000 students, 59% are males. If two students from this college are selected at random, what is the probability that they are of the same gender?

P(S) = 0.5162 or 51.62%

the probability that they are of the same gender is 0.5162 or 51.62%

Step-by-step explanation:

The probability that the two selected students are of the same gender P(S) is;

P(S) = Probability that they are both male P(M) + probability that they are both female P(F)

P(S) = P(M) + P(F) 1

Given;

Proportion of male = 59% = 0.59

Proportion of female = 1-0.59 = 0.41

P(M) = 0.59×0.59 = 0.3481

P(F) = 0.41 × 0.41 = 0.1681

From equation 1;

P(S) = 0.3481 + 0.1681

P(S) = 0.5162 or 51.62%

the probability that they are of the same gender is 0.5162 or 51.62%

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.