1. Two masses are attracted to each other by a force of 3.4 X 10-2 N. What would be the force of attraction if the masses of each were doubled and the distance between them kept constant? 2. Referring to problem 1, what would be the force if one mass was doubled, the other mass tripled and the distance between them 1/2 the original separation distance?

3. Planet Z has a radius 10 times that of the earth and a mass that is 20 times as much. How much would a 160 lb man on the earth weigh on planet Z?

4. What would be the mass of the man in problem 3; a.) on the earth b.) on planet Z?

5. How is the acceleration due to gravity affected if the distance from the center of gravity is; a.) doubled? b.) tripled? c.) 1/4?

6. Calculate the acceleration due to gravity at an altitude of 6.37 X 106 m above the earth's surface.

7. How much would a 30 kg mass weigh at the earth's surface?

8. How much would the 30 kg mass in problem 7 weigh at an altitude of 6.37 X 106m above the earth's surface?

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

the components of a vector are the parts of the vectors that are to each other.

b perpendicular

the speed of the cart after 3 seconds of low fan speed is ⇒ 54.0 cm/s.

the speed of the cart after 5 seconds of medium fan speed is ⇒ 120.0 cm/s.

the speed of the cart after 2 seconds of high fan speed is ⇒ 64.0 cm/s. 

just did the lab.