Pls answer anyone out there pls pls pls

See below.

Step-by-step explanation:

9.

Property of a rhombus:

In a rhombus, the diagonals are perpendicular.

The sum of the measures of the angles of a triangle is 180 deg.

Since the diagonals are perpendicular, the angles formed by the intersection of the diagonals are right angles and measure 90 deg.

m<ABD + m<CAB + 90 = 180

50 + m<CAB + 90 = 180

m<CAB + 140 = 180

(i) m<CAB = 40

The diagonals of a rhombus divide the rhombus into 4 congruent triangles.

Call the point of intersection of the diagonals E.

Triangles CEB and AEB are congruent.

m<BCA = m<DCA = 40

m<BCD = m<BCA + m<DCA = 40 + 40

(ii) m<BCD = 80

m<CDB = m<ADB = 50

m<ADC = m<CDB + m<ADB = 50 + 50

(iii) m<ADC = 100

10.

There are two angles labeled z. One is near point E and one is near point O. One of them probably is x.

Two angles measure 60 and 80. Add them to get 140.

z (near point O) and the 140 deg angle are a linear pair. their measures add to 180 deg.

z + 140 = 180

z = 40 (This is the z near point O.)

z (near point O) and 60 deg add to an interior angle of the parallelogram.

z + 60 = 40 + 60 = 100

The interior angle at vertex O measures 100 deg.

Adjacent interior angles of a parallelogram are supplementary.

100 + y = 180

y = 80

The two angles labeled z are alternate interior angles. Since the sides of a parallelogram are parallel, the two angles labeled z are congruent and measure 40 deg.

z = 40 (This is angle z near point E)

77

step-by-step explanation: