A company has 3 staff positions to fill. If there are 14 candidates, how many outcomes are possible?

364

Step-by-step explanation:

You need to choose 1 out 14 for the first position, then 1 out of the 13 left  for the second position, then 1 out the 12 left for the third position.

That gives 14 * 13 * 12 = 2184.

If order mattered, that would be the answer, but in this case, since order does not matter, the 3 positions can be filled in 3 * 2 * 1 ways = 6 ways.

2184/6 = 364

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.