What is the probability that a junior non-Nutrition major and then a sophomore Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

0.0032

The complete question as seen in other website:

There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

Step-by-step explanation:

Total number of in a nutrition class = 111 students

To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.

Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)

Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)

There are 13 number of junior non-Nutrition major

Pr (j non-N) = 13/111

Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)

Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)

There are 3 number of sophomore Nutrition major

Pr (S N-major) = 3/111

The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111

= 39/12321

= 0.0032