The slope-intercept form of the equation of a line that passes through the point (–2, –13) is y = 5x – 3. What is the point-slope form of the equation for this line? y – 13 = 5(x – 2)
y + 13 = 5(x + 2)
y – 2 = 5(x – 13)
y + 2 = 5(x + 13)

y+13 = 5(x+2)

Step-by-step explanation:

y = 5x – 3

This is in slope intercept form  y = mx+b so the slope is m which is 5

We have a slope and a point ( -2, -13)

Point slope form is

(y-y1) = m(x-x1)

y - -13 = 5(x--2)

y+13 = 5(x+2)

table 3 represents a direct variation function. : )