Consider the quadratic function shown below who's leading coefficient is equal to 1. a. Write the equation of this quadratic in y=(x-h)^2 +k form

b. Find the zeros of tjis quadratic in sinplest radical form

c. Write the equation of this quadratic function in y=ax^2+vs+c, i. e standard form​

m∠a is 90°

m∠b is 40°

answer: rolling a number cube and flipping a coin.

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct