Mathematics, 22.06.2020 20:57 juliomeadaptas

(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y
{-2, 1}
{-2, 3}
{}

$(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y{-2, 1}{-2, 3}{}$

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(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y
{-2, 1}
{-2, 3}
{}
...

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