PLI HELP ME ASAP!
Lisa chooses x boys and y girls to join a Mathematics Competition. The total number of pupils chosen is not more than 24 and the number of girls exceeding the number of boys at least by 4

a) Write two linear inequalities
b) Calculate the minimum and maximum number of girls if Lisa chooses 8 boys

Step-by-step explanation:

a)

total no. of pupils is not more than 24

therefore first equation is

(x+y) ≤ 24. (1)

No. of girls exceeding the no. of boys by atleast 4

(y-x) ≥ 4. (2)

b) Now Liza chooses 8 boys

Maximum no. of girls = ?

Using first inequality

y+8= 24 ( maximum value of less than or equal to function is equal to itself)

Therefore,

y= 24-8

=16

Minimum no. of girls = ?

Using second inequality

y-8 =4 (minimum value of greater than or equal to function is equal to itself)

Therefore,

y= 4+8

y=12

a) 2linear inequalities

(x+y) ≤ 24

(y-x) ≥ 4

b) Max no. of girls = 16

Min no. of girls = 12

Hope it helps...

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

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