A shoe manufacturer determines that its monthly revenue, R(q)R(q)R, (, q, ), in dollars, is given by the function defined above, where qqq is the number of pairs of shoes sold each month. What is the maximum value of the company's monthly revenue in dollars

$9500

Question:

A shoe manufacturer determines that its monthly revenue, R(q)=−0.31(q−260)^2 + 9500 in dollars, is given by the function defined above, where qqq is the number of pairs of shoes sold each month. What is the maximum value of the company's monthly revenue in dollars?

Step-by-step explanation:

To determine the maximum value of the company's monthly revenue in dollars, we need to find the value of q such that we would have the highest value of R(q).

Given expression:

R(q) = −0.31 × (q−260)^2 + 9500

Let's determine the value of R(q) when q is less than 260; greater than 260; and equal to 260.

For example, if q = 100

R(q) = -0.31×(100-260)² + 9500 = $1564

If q = 300

R(q) = -0.31×(300-260)² + 9500 = $9004

If q = 260

R(q) = -0.31×(260-260)² + 9500 = $9500

From the above, R(q) = −0.31 × (q−260)^2 + 9500 would always have a lesser value when q is not equal 260.

Therefore, R(q) is at its maximum when q = 260.

R(260) = $9500

The maximum value of the company's monthly revenue in dollars = $9500

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

step-by-step explanation:

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