A line is parallel to y = 3x + 8 and intersects the point (-3, 7). What is the
equation of this parallel line?
y = [?]X + [ ]

y= 3x+16

Step-by-step explanation:

y = 3x + 8 ║ y= mx +b

Since lines are parallel, m=3

y= 3x+b

(-3, 7) intersect

y= 3x+16

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

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