Lila flies a drone in the direction of 90° towards Avery. Once she gets to Avery she changes course and flies in the direction of 200° towards Mark. Lila and Avery are 20 feet apart; Mark and Avery are 30 feet apart. How far apart are Mark and Lila?

29.8ft

Step-by-step explanation:

suppose that the angles are measured from an x-axis.

we know that:

Lila and Avery are 20 feet apart.

Mark and Avery are 30 feet apart.

If we locate the position of Lila in the (0, 0)

and we use the relation:

x = r*cos(θ) and y = r*cos(θ)

Then the position of Avery is:

P = (20ft*cos(90°), 20ft*sin(90°)) = (0, 20ft)

and the position of mark will be:

P = (0 + 30ft*cos(200°), 20ft + 30ft*sin(300)) = (-28.2ft, 9.7ft)

And because Lila is at the origin, the distance between Mark and Lila is equal to the module of that vector,

Distance = √((28.2ft)^2 + (9.7ft)^2) = 29.8ft

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

child does not get an education so she can use the molla on junk