Find the zeros of the function below, algebraically. f(x)=(x-2)^2-64

Please show how you got answer and explain :D

x=10 and x=-6

Step-by-step explanation:

f(x)=(x-2)²-64 (Given)

0=(x-2)²-64 (Set equation equal to 0)

64=(x-2)² (Add 64 to both sides)

±8=x-2 (Take the square root of both sides)

Because there are two possible roots, make 2 equations to find both:

8=x-2 and -8=x-2

10=x and -6=x

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

ummm seems that u didnt post the attachement !